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Monthly Archives: July 2017
Proof: Every converging sequence is bounded
Every converging sequence is bounded. Proof: Let the sequence is converging to ie Lets choose as the sequence is converging there exists an . Find the
Posted in Real Analysis
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Binet Formula for Fibonacci Number
While there are many ways to derive the recursive formula of Fibonacci Sequence. The formula to find the nth term of a Fibonacci sequence is a beautiful formula. We are not going to derive here but prove the formula using … Continue reading
Posted in Mathematical Induction, Number Theory, Proof
Tagged Fibonacci Number, Recursion, Strong Induction
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Number of terms in Binomial, Multinomial Expansion
Well we know that in expansion there are terms. The question is why ? The answer is the general term of this expansion is where and if we all as one of the solution we have a total of solutions … Continue reading
Posted in Uncategorized
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Fibonacci Numbers through combinatorics
Here is one way to think about Fibonacci Numbers. 1. There are number of balls of only two colors (Let these be red and blue). 2. The red balls are identical and so are blue balls. 3. No two red … Continue reading
Proof of Sequence not marching to zero implies Series is not converging
If a sequence is not marching to zero then the series is not converging.
Posted in Real Analysis
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Prove that a converging sequence has only one limit point
This is another standard theorem in introductory real analysis. There are two ways one can prove it. One by using Triangle Inequality and other by using Proof by contradiction. Given: is a sequence that converges to both and . and … Continue reading
Proof that e is Irrational
To prove that is irrational one can show that . But before one can do that one must show that is bounded above because power series is infinite. This can be done surprisingly similar to what Oresme did for the … Continue reading
Posted in Famous Problem, Proof, Proof by Contradiction, Series
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Peano’s Axiom
Following are the 5 Axioms of Peano or also called as Peano’s Postulates N1. N2. If N3. is not the successor of any element in . N4. If two numbers have the same successor then N5. A subset of which … Continue reading
Posted in Real Analysis
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Bernoulli Inequality proof by Mathematical Induction, AM GM Inequality
This is the proof of Bernoulli Inequality for positive integers using Mathematical Induction This is the proof for the case when the power is between 0 and 1
Posted in Uncategorized
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Density of Rational Numbers in Real Numbers
The idea is that between any two real numbers there is a rational number. To prove this we use Archimedean Property. Let .