Tag Archives: AM GM

Permutation of fractions

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Arithmetic Geometric Inequality Polya’s Proof

This is a proof proposed by Polya It is based on the idea  

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AM GM Proof using Induction

This proof is by Cauchy and uses Mathematical induction For P(2): Assuming its true for . Therefore P(k): For n = k+1 we have Since the truth of P(k+1) follows from truth of P(k) hence by PMI its true for … Continue reading

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Arithmetic Geometric Inequality

This is a famous inequality that one should know. The case for two numbers is really easy The case for 4 variables is also pretty straight forward The case for 3 variables is a little bit tricky but can be … Continue reading

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